When I left my last position, my friends and colleagues with whom I’ve worked for years gave me a little challenge: a PDF with a hidden ciphertext. At first I had to use Excel to decipher the ciphertext, but later I wrote a small Python tool to help me.

The simple ciphers supported by this tool are XOR, ROT, Vigenère and subtract (I added that last one because it was used in a maldoc). You can use the man page (option -m) to learn more.

cipher-tool_V0_0_1.zip (https)
MD5: B7D44090A76F66D7194D0A0D890E2CEB
SHA256: 1E8E1F112595FC08C3C20A06D172C21DDE6375EC8651A8DE6EF57B938F3E67E8

This new version of xor-kpa adds the option -x to encode/decode, and also prints the hexadecimal value of the found keys.

xor-kpa_V0_0_4.zip (https)
MD5: FCE75B6125104D8AFC56A67B65FF75C0
SHA256: 3DCCA479D4C8CAC9B248B24F799184A69D0F10403593CB002248DD35CCE60FD4

When cracking Active Directory passwords as I explained in this series of blog posts, you can also crack the password history.

The program I’m releasing now will make a report of users who “recycle” their previous passwords by using a common string.

Example:

The man page:

Usage: password-history-analysis.py [options] [[@]file ...]
Program to analyze password history

Arguments:
@file: process each file listed in the text file specified
wildcards are supported

Source code put in the public domain by Didier Stevens, no Copyright
Use at your own risk
https://DidierStevens.com

Options:
  --version             show program's version number and exit
  -h, --help            show this help message and exit
  -m, --man             Print manual
  -o OUTPUT, --output=OUTPUT
                        Output to file
  -s SEPARATOR, --separator=SEPARATOR
                        Separator used in the password files (default :)
  -l, --lowercase       Convert usernames to lowercase
  -n, --nonmatching     Print lines that do not match a password entry
  -L LENGTH, --length=LENGTH
                        Minimum length common string

Manual:

This program analyzes files with password history, and reports
statistics on common strings (prefix, suffix, infix) of passwords per
user.
The minimum lenght of a common string is 3 characters by default. Use
option -L to change the minimum length of the common string.


Example of input file (passwords.txt):
user01:HASH:azerty-
user01_history0:HASH:azerty0
user01_history1:HASH:azerty1
user01_history2:HASH:azerty2
user01_history3:HASH:azerty3
user01_history4:HASH:azerty4
user01_history5:HASH:azerty5
user01_history6:HASH:azerty6
user01_history7:HASH:azerty7
user01_history8:HASH:azerty8
user01_history9:HASH:azerty9
user01_history10:HASH:azerty10
user01_history11:HASH:azerty11
user01_history12:HASH:azerty12
user01_history13:HASH:azerty13
user01_history14:HASH:azerty14
user01_history15:HASH:azerty15
user01_history16:HASH:azerty16
user01_history17:HASH:azerty17
user01_history18:HASH:azerty18
user01_history19:HASH:azerty19
user01_history20:HASH:azerty20
user01_history21:HASH:azerty21
user01_history22:HASH:azerty22
user02:HASH:99Monkey
user02_history0:HASH:00Monkey
user02_history1:HASH:01Monkey
user02_history2:HASH:02Monkey
user02_history3:HASH:03Monkey
user02_history4:HASH:04Monkey
user02_history5:HASH:05Monkey
user02_history6:HASH:06Monkey
user02_history7:HASH:07Monkey
user02_history8:HASH:08Monkey
user02_history9:HASH:09Monkey
user02_history10:HASH:10Monkey
user02_history11:HASH:11Monkey
user02_history12:HASH:12Monkey
user02_history13:HASH:13Monkey
user02_history14:HASH:14Monkey
user02_history15:HASH:15Monkey
user02_history16:HASH:16Monkey
user02_history17:HASH:17Monkey
user02_history18:HASH:18Monkey
user02_history19:HASH:19Monkey
user02_history20:HASH:20Monkey
user02_history21:HASH:21Monkey
user02_history22:HASH:22Monkey
user03:HASH:SomethingElse
user03_history0:HASH:Password0
user03_history1:HASH:Password1
user03_history2:HASH:Password2
user03_history3:HASH:Password3
user03_history4:HASH:Password4
user03_history5:HASH:Password5
user03_history6:HASH:Password6
user03_history7:HASH:Password7
user03_history8:HASH:Password8
user03_history9:HASH:Password9
user03_history10:HASH:Password10
user03_history11:HASH:Azerty$1

Usage example:
password-history-analysis.py passwords.txt

Output:
user01:24:24:100.00:azerty
user02:24:24:100.00:Monkey
user03:13:11:84.62:Password

The first field is the username.
The second field is the number of passwords for the given username.
The third field is the largest number of passwords for the given
username with the same prefix or suffix.
The fourth field is the percentage of third and second field.
The fifth field is the password's common string.

The report can be written to file with option -o.
Use option -l to convert usernames to lowercase.

Option -n will not produce a report, but output all lines that do not
match a password entry. Use this to detect entries not handled by this
program.

The separator (for input and output) is :, and can be changed with
option -s.

password-history-analysis_v0_0_1.zip (https)
MD5: 2ED7FB5E6968B25AEBF623754E5513B0
SHA256: DA75A8E2C92DCD31FB3C05732C660C3996EAEBADFA198535C051DC02AE94805B

I released a tool to analyze password history.

To extract password history from ntds.dit with ntdsxtract/dsusers.py, use option –passwordhistory.

To extract password history from ntds.dit with secretsdump.py, use option -history.

Here is how to crack a ZIP password with John the Ripper on Windows:

First you generate the hash with zip2john:

Then you run john:

In this example, I use a specific pot file (the cracked password list).

Quickpost info

Some small changes to my XOR known plaintext attack tool (xor-kpa), which will be detailed in an ISC Diary entry.

xor-kpa_V0_0_5.zip (https)
MD5: 023D8E3725E0EF7CEC449085AA96BB3A
SHA256: 7517DD44AFBFA11122FD940D76878482F50B7A2A2BCD1D7A2AF030F6CAC4F4E3

In this series of blog posts, I’ll explain how I decrypted the encrypted PDFs shared by John August (John wanted to know how easy it is to crack encrypted PDFs, and started a challenge).

Here is how I decrypted the “easy” PDF (encryption_test).

From John’s blog post, I know the password is random and short. So first, let’s check out how the PDF is encrypted.

pdfid.py confirms the PDF is encrypted (name /Encrypt):

pdf-parser.py can tell us more:

The encryption info is in object 26:

From this I can conclude that the standard encryption filter was used. This encryption method uses a 40-bit key (usually indicated by a dictionary entry: /Length 40, but this is missing here).

PDFs can be encrypted for confidentiality (requiring a so-called user password /U) or for DRM (using a so-called owner password /O). PDFs encrypted with a user password can only be opened by providing this password. PDFs encrypted with a owner password can be opened without providing a password, but some restrictions will apply (for example, printing could be disabled).

QPDF can be used to determine if the PDF is protected with a user password or an owner password:

This output (invalid password) tells us the PDF document is encrypted with a user password.

I’ve written some blog posts about decrypting PDFs, but because we need to perform a brute-force attack here (it’s a short random password), this time I’m going to use hashcat to crack the password.

First we need to extract the hash to crack from the PDF. I’m using pdf2john.py to do this. Remark that John the Ripper (Jumbo version) is now using pdf2john.pl (a Perl program), because there were some issues with the Python program (pdf2john.py). For example, it would not properly generate a hash for 40-bit keys when the /Length name was not specified (like is the case here). However, I use a patched version of pdf2john.py that properly handles default 40-bit keys.

Here’s how we extract the hash:

This format is suitable for John the Ripper, but not for hashcat. For hashcat, just the hash is needed (field 2), and no other fields.

Let’s extract field 2 (you can use awk instead of csv-cut.py):

I’m storing the output in file “encryption_test – CONFIDENTIAL.hash”.

And now we can finally use hashcat. This is the command I’m using:

hashcat-4.0.0\hashcat64.exe --potfile-path=encryption_test.pot -m 10400 -a 3 -i "encryption_test - CONFIDENTIAL.hash" ?a?a?a?a?a?a

I’m using the following options:

• –potfile-path=encryption_test.pot : I prefer using a dedicated pot file, but this is optional
• -m 10400 : this hash mode is suitable to crack the password used for 40-bit PDF encryption
• -a 3 : I perform a brute force attack (since it’s a random password)
• ?a?a?a?a?a?a : I’m providing a mask for 6 alphanumeric characters (I want to brute-force passwords up to 6 alphanumeric characters, I’m assuming when John mentions a short password, it’s not longer than 6 characters)
• -i : this incremental option makes that the set of generated password is not only 6 characters long, but also 1, 2, 3, 4 and 5 characters long

And here is the result:

The recovered password is 1806. We can confirm this with QPDF:

Conclusion: PDFs protected with a 4 character user password using 40-bit encryption can be cracked in a couple of seconds using free, open-source tools.

FYI, I used the following GPU: GeForce GTX 980M, 2048/8192 MB allocatable, 12MCU

Update: this is the complete blog post series:

• • • Cracking Encrypted PDFs – Part 1: cracking the password of a PDF and decrypting it (what you are reading now)
    • Cracking Encrypted PDFs – Part 2: cracking the encryption key of a PDF
    • Cracking Encrypted PDFs – Part 3: decrypting a PDF with its encryption key
  • • Cracking Encrypted PDFs – Conclusion: don’t use 40-bit keys

After cracking the “easy” PDF of John’s challenge, I’m cracking the “tough” PDF (harder_encryption).

Using the same steps as for the “easy” PDF, I confirm the PDF is encrypted with a user password using 40-bit encryption, and I extract the hash.

Since the password is a long random password, a brute-force attack on the password like I did in the first part will take too long. That’s why I’m going to perform a brute-force attack on the key: using 40-bit encryption means that the key is just 5 bytes long, and that will take about 2 hours on my machine. The key is derived from the password.

I’m using hashcat again, but this time with hash mode 10410 in stead of 10400.
This is the command I’m using:

hashcat-4.0.0\hashcat64.exe --potfile-path=harder_encryption.pot -m 10410 -a 3 -w 3 "harder_encryption - CONFIDENTIAL.hash" ?b?b?b?b?b

I’m using the following options:

• –potfile-path=harder_encryption.pot : I prefer using a dedicated pot file, but this is optional
• -m 10410 : this hash mode is suitable to crack the key used for 40-bit PDF encryption
• -a 3 : I perform a brute force attack (since it’s a key, not a password)
• -w 3 : I’m using a workload profile that is supposed to speed up cracking on my machine
• ?b?b?b?b?b : I’m providing a mask for 5 bytes (I want to brute-force keys that are 40 bits long, i.e. 5 bytes)

And here is the result:

The recovered key is 27ce78c81a. I was lucky, it took about 15 minutes to recover this key (again, using GPU GeForce GTX 980M, 2048/8192 MB allocatable, 12MCU). Checking the complete keyspace whould take a bit more than 2 hours.

Now, how can we decrypt a PDF with the key (in stead of the password)? I’ll explain that in the next blog post.

Want a hint? Take a look at my Tweet!

Update: this is the complete blog post series:

• • Cracking Encrypted PDFs – Part 1: cracking the password of a PDF and decrypting it
  • Cracking Encrypted PDFs – Part 2: cracking the encryption key of a PDF (what you are reading now)
  • Cracking Encrypted PDFs – Part 3: decrypting a PDF with its encryption key
  • Cracking Encrypted PDFs – Conclusion: don’t use 40-bit keys

I performed a brute-force attack on the password of an encrypted PDF and a brute-force attack on the key of (another) encrypted PDF, both PDFs are part of a challenge published by John August.

The encryption key is derived from the password. it’s not just based on the password only, but also on metadata. This implies that different PDFs encrypted with the same user password, will have different encryption keys.

When you recover the user password of an encrypted PDF, you can just use it with PDF readers like Adobe Reader: they will ask you for the password, you provide it and the PDF will be decrypted and rendered.

But when you recover the key of an encrypted PDF, you can not use it with PDF reader: there is no feature that will allow you to input a key in stead of a password. The only method I knew to decrypt a PDF document with its encryption key, was to use Elcomsoft’s PDF cracking tool:

Now I worked out a second method: I modified the source code of QPDF so that it will accept encryption keys too. It’s a quick and dirty hack, I did not add a new option to QPDF but I “hijacked” the –password option. If the value to the option –password starts with string “key:”, then QPDF will not derive the key from the provided password, but it will use the key provided as hexadecimal characters. Here is how I use it to decrypt the “tough” PDF:

I also made a small modification to the –show-encryption option, to display the encryption key:

Update: I had an email exchange with Jay Berkenbilt, the author of QPDF, and he will look into this patch and possibly add a new key option to QPDF.

If you are interested in my modified version of QPDF, you can find the modified source code files and Windows binaries here:

qpdf-patched.zip (https)
MD5: 57E1A5A232E12B45D0A927181A1E8C3B
SHA256: 6F17E095B38AE72F229A6662216DDCE86057D2BA1C567B07FEF78B8A93413495

Update: this is the complete blog post series:

• • Cracking Encrypted PDFs – Part 1: cracking the password of a PDF and decrypting it
  • Cracking Encrypted PDFs – Part 2: cracking the encryption key of a PDF
  • Cracking Encrypted PDFs – Part 3: decrypting a PDF with its encryption key (what you are reading now)
  • Cracking Encrypted PDFs – Conclusion: don’t use 40-bit keys

TL;DR: PDFs protected with 40-bit keys can not guarantee confidentiality, even with strong passwords. When you protect your PDFs with a password, you have to encrypt your PDFs with strong passwords and use long enough keys. The PDF specification has evolved over time, and with it, the encryption options you have. There are many encryption options today, you are no longer restricted to 40-bit keys. You can use 128-bit or 256-bit keys too.

There is a trade-off too: the more advanced encryption option you use, the more recent the PDF reader must be to support the encryption option you selected. Older PDF readers are not able to handle 256-bit AES for example.

Since each application capable of creating PDFs will have different options and descriptions for encryption, I can not tell you what options to use for your particular application. There are just too many different applications and versions. But if you are not sure if you selected an encryption option that will use long enough keys, you can always check the /Encrypt dictionary of the PDF you created, for example with my pdf-parser (in this example /Length 128 tells us a 128-bit key is used):

Or you can use QPDF to encrypt an existing PDF (I’ll publish a blog post later with encryption examples for QPDF).

But don’t use 40-bit keys, unless confidentiality is not important to you:

I first showed (almost 4 years ago) how PDFs with 40-bit keys can be decrypted in minutes, using a commercial tool with rainbow tables. This video illustrates this.

Later I showed how this can be done with free, open source tools: Hashcat and John the Ripper. But although I could recover the encryption key using Hashcat, I still had to use a commercial tool to do the actual decryption with the key recovered by Hashcat.

Today, this is no longer the case: in this series of blog posts, I show how to recover the password, how to recover the key and how to decrypt with the key, all with free, open source tools.

Overview of the complete blog post series:

• • Cracking Encrypted PDFs – Part 1: cracking the password of a PDF and decrypting it
  • Cracking Encrypted PDFs – Part 2: cracking the encryption key of a PDF
  • Cracking Encrypted PDFs – Part 3: decrypting a PDF with its encryption key
  • Cracking Encrypted PDFs – Conclusion: don’t use 40-bit keys (what you are reading now)

The Office Open XML format introduced with MS Office 2007, is essentially composed of XML files stored inside a ZIP container.

When an OOXML file (like a .docx file) is protected with a password for reading, it is encrypted. The encrypted OOXML file is stored inside a Compound File Binary Format file, or what I like to call an OLE file. This is the “old” MS Office file format (like .doc), the default file format used before MS Office 2007.

This is how an encrypted .docx file looks like, when analyzed with oledump:

Stream EncryptedPackage contains the encrypted document, and stream EncryptionInfo contains information necessary to help with the decryption of stream EncryptedPackage.

The structure of stream EncryptedPackage is simple:

First there’s an integer with the size of the encrypted document, followed by the encrypted document. If we decode the binary data for the integer with format-bytes.py, we get the size 11841:

The EncryptionInfo stream starts with binary data, the version format, and is then followed by more binary data, or XML data, depending on the version:

The first bytes specify the major and minor version used for the EncryptionInfo stream. This example is mostly XML:

Which can be further parsed with xmldump.py:

To help identifying what version is used, I developed an oledump plugin named plugin_office_crypto:

Depending on the version, different tools can be used to decrypt office documents.

Python program msoffcrypto-tool can only decrypt agile encryption (for the moment, it’s a work in progress).

C program msoffice-crypt can decrypt standard, extended and agile encryption.

Sometimes, malicious documents will be encrypted to try to avoid detection. The victim will have to enter the password to open the document. There is one exception though: Excel documents encrypted with password VelvetSweatshop.

keihash.py is a program to parse pcap files and calculate the KEIHash of SSH connections.

The KEIHash is the MD5 hash of the Key Exchange Init (KEI) data (strings). For obvious reasons, I could not call this an SSH fingerprint. This is inspired by JA3 SSL fingerprinting.

It can be used to profile SSH clients and servers. For example, the hash for the latest version of PuTTY (SSH-2.0-PuTTY_Release_0.70) is 1c5eaa56f3e4569385ae5f82a54715ee.

This is the MD5 hash of:

240-curve25519-sha256@libssh.org,ecdh-sha2-nistp256,ecdh-sha2-nistp384,ecdh-sha2-nistp521,diffie-hellman-group-exchange-sha256,diffie-hellman-group-exchange-sha1,diffie-hellman-group14-sha1,rsa2048-sha256,rsa1024-sha1,diffie-hellman-group1-sha1;87-ssh-rsa,ssh-ed25519,ecdsa-sha2-nistp256,ecdsa-sha2-nistp384,ecdsa-sha2-nistp521,ssh-dss;189-aes256-ctr,aes256-cbc,rijndael-cbc@lysator.liu.se,aes192-ctr,aes192-cbc,aes128-ctr,aes128-cbc,chacha20-poly1305@openssh.com,blowfish-ctr,blowfish-cbc,3des-ctr,3des-cbc,arcfour256,arcfour128;189-aes256-ctr,aes256-cbc,rijndael-cbc@lysator.liu.se,aes192-ctr,aes192-cbc,aes128-ctr,aes128-cbc,chacha20-poly1305@openssh.com,blowfish-ctr,blowfish-cbc,3des-ctr,3des-cbc,arcfour256,arcfour128;155-hmac-sha2-256,hmac-sha1,hmac-sha1-96,hmac-md5,hmac-sha2-256-etm@openssh.com,hmac-sha1-etm@openssh.com,hmac-sha1-96-etm@openssh.com,hmac-md5-etm@openssh.com;155-hmac-sha2-256,hmac-sha1,hmac-sha1-96,hmac-md5,hmac-sha2-256-etm@openssh.com,hmac-sha1-etm@openssh.com,hmac-sha1-96-etm@openssh.com,hmac-md5-etm@openssh.com;9-none,zlib;9-none,zlib;0-;0-

These are all the strings found in the Key Exchange Init packet, prefixed by their length and concatenated with separator ;.

With this, I’ve been able to identify SSH clients with spoofed banners attempting to connect to my servers.

keihash_V0_0_1.zip (https)
MD5: 674D019A739679D9659D2D512A60BDD8
SHA256: DB7471F1253E3AEA6BFD0BA38C154AF3E1D1967F13980AC3F42BB61BBB750490

This is a new tool to recover the password of encrypted MS Office documents. I quickly put together this script to help with the analysis of encrypted, malicious documents.

This tool relies completely on Python module msoffcrypto to decrypt MS Office documents.

Since this is a Python tool based on a Python library, don’t except fast password recovery. This is more a convenience program.

It can recover passwords using a build-in password list, or you can provide your own list via option -p.

The tool can also decrypt the encrypted MS Office document if the password is recovered: used option -o to achieve this. Otherwise, the tool just displays the recovered password.

Like many of my tools, it can take its input from stdin and provide the decrypted document via stdout.

It’s developed with Python 2, and also tested on Python 3.

Read the man page for all the details: option -m.

msoffcrypto-crack_V0_0_1.zip (https)
MD5: F67060E0DE62727A1A69D0FD6F39013A
SHA256: 1466B94B56595BA0B91F0A2606F699E1D737E964F3F1A4DFDF7EAA47843DD063

In this update of msoffcrypto-crack.py, two new options were added:

-e takes a text file and extracts all words from this text file to be used in the dictionary attack. Words are strings delimited by space characters. Words between single or double quotes, and words after string “password” are put at the beginning of the list for the dictionary attack.

The idea for option -e, is that you give it the content of an email message that contains the password of the encrypted attachment(s).

-c takes the password to decrypt the document. You use this option after the password was recovered (with option -p or -e for example), and need to run the tool again to decrypt the document. You can run the password cracking each time when you need to decrypt the document, but if this takes too long, then you just run it once and from then on provide the recovered password with option -c.

Password VelvetSweatshop was added to the embedded password list.

msoffcrypto-crack_V0_0_2.zip (https)
MD5: 010B7FA68FCF9CE84427815EFDFE1C42
SHA256: 6B368E40EEE8A907D444A49963B37F456A3645991201CE06F0E46A0F2E188A74

This is a bug fix update: for agile encryption, Python module msoffcrypto does not throw an exception in method load_key when an invalid password is provided. It throws an exception when an attempt is made to decrypt the file.

I added a call to method decrypt to handle this case.

msoffcrypto-crack_V0_0_3.zip (https)
MD5: 45BAB81D744DA62182EC58A8F2E05BFE
SHA256: CF9DE02C72C07C07786BE09551CD17F6DBB83BCEF2A1C5435E06A695D7C6770E

One of my first quickposts, more than 10 years ago, was an howto: using openssl to retrieve the certificate of a web site.

Since then, nmap has a scripting engine, and there is a script to check a certificate with nmap: ssl-cert.nse.

You just have to scan the site and port for which you want to check the certificate, like this: nmap -p 443 –script ssl-cert didierstevens.com

If you want the certificate too, increase verbosity with option -v:

Checking a certificate will not work if you scan a port that is not known to provide SSL/TLS:

In that case, you have to use service discovery (-sV):

Quickpost info

I was trying to create a capture file with NTLM authenticated WebDAV traffic, using Responder: I couldn’t get it to work. There was WebDAV traffic, but no NTLMSSP headers.

Long story short: there’s a bug in Responder version 2.3.3.9. It manifests itself when the WebDAV client sends a request with just headers, and “Content-Length: 0”, like this:

The code in Responder “sees” just “Content-Length” and waits for more packets:

I made a quick & dirty fix: break out of the loop when we see “Content-Length: 0” (servers/HTTP.py):

And now I have NTLMSSP headers:

I just start my modified version of Responder:

Generate WebDAV traffic from a Windows 7 client:

And Responder participates in the challenge:

This can of course be cracked (if the password is not too complex), with John The Ripper for example:

I also have a blog post with more details about WebDAV traffic from Windows clients.

Once I got Responder to work, I searched on Laurent’s Responder repository, and found a pull-request to fix issues with “Content-Length: 0” requests (this PR has not been merged yet). Hence I’m not going to do my own PR.

You can find the capture file here:

webdav-ntlm-responder.zip (https)
MD5: A427DDBDAF090E93BB75B7A8DE696826
SHA256: 2F92CDD7382DD3622AC1F8769CF9D065C60C235DEF764E6709C32E2C4A7554A8

Microsoft’s patch for CVE-2020-0601 introduces a call to CveEventWrite in CryptoAPI when a faked certificate is detected.

This will write a Windows event entry in the Application event log.

For all of you out there in restricted corporate environments who need to test the processing of this event log entry, I wrote some VBA code to generate this event. The generated event will mimic a CVE-2020-0601 warning to some extent (didn’t bother getting para and otherPara right).

Copy the VBA code below in an Office application that supports VBA, like Word, and run the code. Then check your Application event log.

Option Explicit

'VBA7
Declare PtrSafe Sub CveEventWrite Lib "advapi32" (ByVal CveId As String, ByVal AdditionalDetails As String)

Sub TestCveEventWrite()
    Dim strCveId As String
    Dim strAdditionalDetails As String

    strCveId = "[CVE-2020-0601] cert validation"
    strAdditionalDetails = "CA: <@DidierStevens> sha1: 7A036FBBDBF7F29A3821A8087CE177E60927A6F3 para: something otherPara: something"
    CveEventWrite StrConv(strCveId, vbUnicode), StrConv(strAdditionalDetails, vbUnicode)
End Sub

This new version of msoffcrypto-crack.py, a tool to crack encrypted MS Office documents, comes with a new option to generated a password dictionary based on the filename of the document.

Option -p allows the user to provide a dictionary file. Use value #f to generate a dictionary based on the filename: This will generate a dictionary of all possible substrings of the filename.

I had to analyze an encrypted spreadsheet yesterday, and the password was in the name, like this:

msoffcrypto-crack_V0_0_5.zip (https)
MD5: 1514DA367DCFF7051AB117266CE65BD3
SHA256: FEEFDD89134083EA19936494C8FCBD05804B3B9C0D4C5FBAFE06578D466B50AE

This new version of zipdump uses module pyzipper in stead of build-in module zipfile.

pyzipper supports AES encryption. It is not a built-in module, and needs to be installed (with pip for example). pyzipper does not support Python 2.

If module pyzipper is not installed, zipdump will fall back to module zipfile.

zipdump_v0_0_19.zip (https)
MD5: 6DDE072811D4B44B15D0B8EE4E7B4C03
SHA256: EB38D57E63B12EFAC531B4F0BA866BF47CAEC7F64E0C3CCF4557476FFF1C6226